Where N = # of boli stuffing choices, then V = # of different boli possible!
2 to the Nth power minus 1 = V
With 2 choices of stuffings there are 3 different boli possible:
2 to the 2nd power, minus 1 = 3 varieties of boli
a boli with stuffing A, a boli with stuffing B, and a boli with both A & B
With 3 choices of stuffings there are 7 different boli possible:
2 to the 3rd power, minus 1 = 7 varieties of boli
a boli with stuffing A, a boli with stuffing B, a boli with stuffing C, one with both A&B, both A&C, both B&C, and all three stuffings in one boli A&B&C
With 4 choices of stuffings there are 15 different boli possible:
2 to the 4th power, minus 1 = 15 varieties of boli
A, B, C, D, AB, AC, AD, BC, BD, CD, ABC, ABD, BCD, CDA, & ABCD
With 5 choices of stuffings there are 31 different boli possible:
2 to the 5th power, minus 1 = 31 varieties of boli
A, B, C, D, E, AB, AC, AD, AE, BC, BD, BE, CD, CE, DE, ABC, ABD, ABE, ACD, ACE, ADE, BCD, BCE, BDE, CDE, ABCD, ABCE, ABDE, ACDE, BCDE & ABCDE
With 10 choices of stuffings there are 1024 different boli possible
With 20 choices of stuffings there are 1,074,176 different boli possible
With 30 choices of stuffings there are approximately
1.1 BILLION different boli !!!!
But…sorry, we couldn’t physically make a boli with 30 different stuffings,
so try the My Favorite boli with your choice of 5 different stuffings!! |